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Go Math Answer Key

Texas Go Math Grade 5 Lesson 8.3 Answer Key Multiplication and Division Equations

Refer to our Texas Go Math Grade 5 Answer Key Pdf to score good marks in the exams. Test yourself by practicing the problems from Texas Go Math Grade 5 Lesson 8.3 Answer Key Multiplication and Division Equations.

Unlock the Problem

Jake is buying a movie ticket and a box of popcorn for $12. The ticket costs 2 times as much as the popcorn. How much does the popcorn cost? How much does the ticket cost? The cost of the tickets is 2 × p, where p is the price of the popcorn.

• How does knowing that a ticket costs 2 times as much as the popcorn help you choose an operation to write an expression? ________________________ The expression is 2 x p + p = $12

Use a related equation.

Texas Go Math Grade 5 Lesson 8.3 Answer Key 1

The popcorn costs p is $4 . Label the strip for the popcorn. It represents 1 unit. The cost of the ticket is 2 x p times as much. Label the strips for the ticket. The total cost is $12 . 3 units are shown in the model.

Texas-Go-Math-Grade-5-Lesson-8.3-Answer-Key-2

To find a missing factor, We have to write a division equation that is related to the multiplication equation. Then divide. 12 ÷ 3 = p 4 = p So, 1 bag of popcorn costs  $4. The cost 1 tickets is 2 times the cost of 1 bag of popcorn. 2 x $4 = $8 So, 1 ticket costs $8.

Use a related equation. Katrina buys a package of trading cards. She divides the cards into 4 equal piles. Each pile contains 12 cards. The equation that describes the number of cards in the package is c ÷ 4 = 12. How many cards were in the package when Katrina bought it?

Texas Go Math Grade 5 Lesson 8.3 Answer Key 3

SOLVE Write a related multiplication equation. Multiplication equation: _____________ c = ____________ So, the package Katrina bought had _________ trading cards in it. Answer: c ÷ 4 = 12 Multiplication equation: c = 12 x 4 c = 48 So, the package Katrina bought had 48 trading cards in it. Explanation: Katrina buys a package of trading cards. She divides the cards into 4 equal piles. Each pile contains 12 cards. The equation that describes the number of cards in the package is c ÷ 4 = 12. The multiplication equation is c = 12 x 4 the product is 48. So the value of c is 48. So, the package Katrina bought had 48 trading cards in it.

Math Talk Mathematical Processes

Explain how the strip diagrams for multiplication and division are related. Answer:

Share and Show

Use the strip diagrams to write an equation. Then solve.

Texas Go Math Grade 5 Lesson 8.3 Answer Key 4

Problem Solving

Practice: Copy and Solve Use a strip diagram or a related equation to solve. Check your solution.

Question 3. 128 = 8 × d Answer: 128 = 8 × d Related equation: 128 ÷  8 = d 16 = d Explanation: The given equation is 128 = 8 x d. We have to find out the d value. So, the related equation for the given equation is 128 ÷  8 = d. Perform division operation on 128 ÷  8 the quotient is 16. The value of d is 16.

Question 4. r ÷ 9 = 17 Answer: r ÷ 9 = 17 Related equation: r = 17 x 9 r = 153 Explanation: The given equation is r ÷ 9 = 17. We have to find out the r value. So, the related equation for the given equation is r = 17 x 9. Perform multiplication operation with 17 and 9 the product is 153. The value of r is 153.

Question 5. 6m = 78 Answer: 6m = 78 Related equation: m = 78 ÷ 6 m = 13 Explanation: The given equation is 6m = 78. We have to find out the m value. So, the related equation for the given equation is 78 ÷  6 = m. Perform division operation on 78 ÷  6 the quotient is 13. The value of m is 13.

Go Math 5th Grade Multiplication Equation Lesson 8.3 Question 6. 7 = b ÷ 17 Answer: 7 = b ÷ 17 Related equation: 7 x 17 = b 119 = b Explanation: The given equation is 7 = b ÷ 17. We have to find out the b value. So, the related equation for the given equation is b = 7 x 17. Perform multiplication operation with 17 and 7 the product is 119. The value of b is 119.

Question 7. How can you justify that j = 348 is the solution to j ÷ 12 = 29? Explain. Answer: The equation is j ÷ 12 = 29 we know that j = 348 Related equation j = 29 x 12 j = 348 The value j = 348 is the solution to j ÷ 12 = 29. Explanation: The given equation is j ÷ 12 = 29. Here j is equal to 348. So, the related equation for the given equation is j = 29 x 12 Perform multiplication operation with 29 and 12 the product is 348. Hence the value j is equal to 348 is the solution to j ÷ 12 = 29.

Texas Go Math Grade 5 Lesson 8.3 Answer Key 6

Question 8. Multi-Step On Friday, the snack bar made $992 selling large buckets of popcorn. How many large buckets of popcorn did the snack bar sell on Friday? In your equation1 let p represent the number of large buckets of popcorn sold. Answer:

Texas Go Math Grade 5 Lesson 8.3 Answer Key 7

Question 10. H.O.T. Multi-Step Asher wants to buy a video game console. In order to save the money needed to buy it in 5 months, he divides the cost by 5. He finds he needs to save $37 a month. What is the total cost, c, of the game console? Answer: Equation: c ÷ 5 = $37 Related equation: c = $37 x 5 c = $185 The total cost of the video game console is $185. Explanation: Asher wants to buy a video game console. In order to save the money needed to buy it in 5 months, he divides the cost by 5. He finds he needs to save $37 a month. The equation is c ÷ 5 = $37. The related equation for the given equation is c = $37 x 5. Perform multiplication operation with 37 and 5 the product is $185. The total cost of the video game console is $185.

Go Math Grade 5 Lesson 8.3 Answer Key Question 11. Representations Mariah bought a bag of buttons. She divides the buttons equally among 15 containers. Each container has 10 buttons. How many buttons does Mariah have? In your equation, let b represent the number of buttons Mariah has. Answer: Equation: b ÷ 15 = 10 Related equation: b = 10 x 15 b = 150 Here b represents the number of buttons does Mariah have. Mariah have 150 buttons. Explanation: Mariah bought a bag of buttons. She divides the buttons equally among 15 containers. Each container has 10 buttons. The equation is b ÷ 15 = 10. The related equation for the given equation is b = 10 x 15. Perform multiplication operation with 10 and 15 the product is 150. Here b represents the number of buttons does Mariah have. Mariah have 150 buttons.

Daily Assessment Task

Fill in the bubble completely to show your answer.

Texas-Go-Math-Grade-5-Lesson-8.3-Answer-Key-5(1)

Texas Test Prep

Texas-Go-Math-Grade-5-Lesson-8.3-Answer-Key-5(4)

Texas Go Math Grade 5 Lesson 8.3 Homework and Practice Answer Key

Use a strip diagram or a related equation to solve.

Check your solution.

Question 1. c ÷ 5 = 13 Answer: c ÷ 5 = 13 Related equation: c = 13 x 5 c = 65 Explanation: The given equation is c ÷ 5 = 13. We have to find out the c value. So, the related equation for the given equation is c = 13 x 5. Perform multiplication operation with 13 and 5 the product is 65. The value of c is 65.

Question 2. 112 = 7 × b Answer: 112 = 7 × b Related equation: 112 ÷ 7 = b 16 = b Explanation: The given equation is 112 = 7 x b. We have to find out the b value. So, the related equation for the given equation is 112 ÷ 7 = b . Perform division operation 112 by 7 the result is 16. The value of b is 16.

Texas Go Math Practice and Homework Lesson 8.3 Answer Key Question 3. 4p = 68 Answer: 4p = 68 Related equation: p = 68 ÷ 4 p = 17 Explanation: The given equation is 4p = 68. We have to find out the p value. So, the related equation for the given equation is 68 ÷ 4 =p . Perform division operation on 68 by 4 the result is 17. The value of p is 17.

Question 4. 9 = d ÷ 21 Answer: 9 = d ÷ 21 Related equation: 9 x 21 = d 189 = d Explanation: The given equation is 9 = d ÷ 21. We have to find out the d value. So, the related equation for the given equation is d = 9 x 21. Perform multiplication operation with 9 and 21 the product is 189. The value of d is 189.

Question 5. 105 = 3 × a Answer: 105 = 3 x a Related equation: 105 ÷ 3 = a 35 = a Explanation: The given equation is 105 = 3 x a. We have to find out the a value. So, the related equation for the given equation is 105 ÷ 3 =a . Perform division operation on 105 by 3 the result is 35. The value of a is 35.

Question 6. 9g = 99 Answer: 9g = 99 Related equation: g = 99 ÷ 9  g = 11 Explanation: The given equation is 9g = 99. We have to find out the g value. So, the related equation for the given equation is g = 99 ÷ 9. Perform division operation on 99 by 9 the result is 11. The value of g is 11.

Question 7. m ÷ 10 = 16 Answer: m ÷ 10 = 16 Related equation: m = 16 x 10  m = 160 Explanation: The given equation is m ÷ 10 = 16. We have to find out the m value. So, the related equation for the given equation is m = 16 x 10. Perform multiplication operations with 16 and 10 the product is 160. The value of m is 160.

Go Math Lesson 8.3 5th Grade Division Answer Key Question 8. 22 = n ÷ 7 Answer: 22 = n ÷ 7 Related equation: 22 x 7 = n 154 = n Explanation: The given equation is 22 = n ÷ 7. We have to find out the n value. So, the related equation for the given equation is n = 22 x 7. Perform multiplication operation with 22 and 7 the product is 154. The value of n is 154.

Question 9. 92 = f × 4 Answer: 92 = f x 4 Related equation: 92 ÷ 4 = f 23 = f Explanation: The given equation is 92 = f x 4. We have to find out the f value. So, the related equation for the given equation is f = 92 ÷ 4. Perform division operation on 92 by 4 the result is 23. The value of f is 23.

Question 10. h ÷ 9 = 14 Answer: h ÷ 9 = 14 Related equation: h = 14 x 9 h = 126 Explanation: The given equation is h ÷ 9 = 14. We have to find out the h value. So, the related equation for the given equation is h = 14 x 9. Perform multiplication operation with 14 and 9 the product is 126. The value of h is 126.

Question 11. 13 = j ÷ 8 Answer: 13 = j ÷ 8 Related equation: 13 x 8 = j 104 = j Explanation: The given equation is 13 = j ÷ 8. We have to find out the j value. So, the related equation for the given equation is 13 x 8 = j. Perform multiplication operation with 13 and 8 the product is 104. The value of j is 104.

Question 12. 165 = 11r Answer: 165 = 11r Related equation: 165 ÷ 11 = r 15 = r Explanation: The given equation is 165 = 11r. We have to find out the r value. So, the related equation for the given equation is r = 165 ÷ 11 . Perform division operation on 165 by 11 the result is 15. The value of r is 15.

Question 13. Sierra arranges fabric squares to sew together to make a blanket for her baby sister. She divides the fabric squares equally among 12 rows. Each row has 8 squares. How many fabric squares does Sierra have? In your equation, let f represent the number of fabric squares Sierra has. Answer: f ÷ 12 = 8 Related equation: f = 8 x 12 f = 96 Here f represent the number of fabric squares does Sierra have. Sierra have 96 fabric squares. Explanation: Sierra arranges fabric squares to sew together to make a blanket for her baby sister. She divides the fabric squares equally among 12 rows. Each row has 8 squares. The equation is f ÷ 12 = 8. The related equation is f = 8 x 12. Multiply 8 with 12 the product is 96. Here f represent the number of fabric squares. Sierra have 96 fabric squares.

Go Math Grade 5 Lesson 8.3 Division Strip Diagrams Question 14. A school district purchased 90 new computers. The computers were divided equally among 6 classrooms. How many new computers are in each classroom? In your equation, let c represent the number of computers in each classroom. Answer: 90 ÷ 6 = c 15 = c Here c represent the number of computers in each classroom. In each classroom there are 15 computers. Explanation: A school district purchased 90 new computers. The computers were divided equally among 6 classrooms. The equation is 90 ÷ 6 = c. Divide 90 by 6 the result is 15. Here c represent the number of computers in each classroom. In each classroom there are 15 computers.

Question 15. Write a real-world problem for the equation 4 × y = 60. Then solve. Answer:

Lesson Check

Fill In the bubble completely to show your answer.

Texas Go Math Grade 5 Lesson 8.3 Answer Key 9

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Answer Key 8.3

  • [latex]12a^4b^5[/latex]
  • [latex]25x^3y^5z[/latex]
  • [latex]x(x-3)[/latex]
  • [latex]4(x-2)[/latex]
  • [latex](x+2)(x-4)[/latex]
  • [latex]x(x-7)(x+1)[/latex]
  • [latex](x+5)(x-5)[/latex]
  • [latex](x+3)(x-3)^2[/latex]
  • [latex](x+1)(x+2)(x+3)[/latex]
  • [latex](x-5)(x-2)(x+3)[/latex]
  • [latex]\begin{array}[t]{rrl} \text{LCD}&=&10a^3b^2 \\ \\ \dfrac{3a}{5b^2}\cdot \dfrac{2a^3}{2a^3} &\Rightarrow &\dfrac{6a^4}{10a^3b^2} \\ \\ \dfrac{2}{10a^3b}\cdot \dfrac{b}{b} &\Rightarrow & \dfrac{2b}{10a^3b^2} \end{array}[/latex]
  • [latex]\begin{array}[t]{rrl} \text{LCD}&=&(x-4)(x+2) \\ \\ \dfrac{3x}{(x-4)}\cdot \dfrac{(x+2)}{(x+2)}&\Rightarrow &\dfrac{3x^2+6x}{(x-4)(x+2)} \\ \\ \dfrac{2}{(x+2)}\cdot \dfrac{(x-4)}{(x-4)}&\Rightarrow &\dfrac{2x-8}{(x-4)(x+2)} \end{array}[/latex]
  • [latex]\begin{array}[t]{rrl} \text{LCD}&=&(x-3)(x+2) \\ \\ \dfrac{(x+2)}{(x-3)}\cdot \dfrac{(x+2)}{(x+2)}&\Rightarrow &\dfrac{x^2+4x+4}{(x-3)(x+2)} \\ \\ \dfrac{(x-3)}{(x+2)}\cdot \dfrac{(x-3)}{(x-3)}&\Rightarrow &\dfrac{x^2-6x+9}{(x-3)(x+2)} \end{array}[/latex]
  • [latex]\begin{array}[t]{rrl} \text{LCD}&=&x(x-6) \\ \\ \dfrac{5}{x^2-6x}&\Rightarrow &\dfrac{5}{x(x-6)} \\ \\ \dfrac{2}{x}\cdot \dfrac{(x-6)}{(x-6)}&\Rightarrow &\dfrac{2x-12}{x(x-6)} \\ \\ \dfrac{-3}{(x-6)}\cdot \dfrac{x}{x}&\Rightarrow & \dfrac{-3x}{x(x-6)} \end{array}[/latex]
  • [latex]\begin{array}[t]{rrl} \text{LCD}&=&(x-4)^2(x+4) \\ \\ \dfrac{x}{x^2-16}\cdot \dfrac{(x-4)}{(x-4)}&\Rightarrow &\dfrac{x^2-4x}{(x-4)^2(x+4)} \\ \\ \dfrac{3x}{(x^2-8x+16)}\cdot \dfrac{(x+4)}{(x+4)}&\Rightarrow &\dfrac{3x^2+12}{(x-4)^2(x+4)} \end{array}[/latex]
  • [latex]\begin{array}[t]{rrl} \text{LCD}&=&(x-5)(x+2) \\ \\ \dfrac{5x+1}{x^2-3x-10}&\Rightarrow &\dfrac{5x+1}{(x-5)(x+2)} \\ \\ \dfrac{4}{(x-5)}\cdot \dfrac{(x+2)}{(x+2)}&\Rightarrow &\dfrac{4x+8}{(x-5)(x+2)} \end{array}[/latex]
  • [latex]\begin{array}[t]{rrl} \text{LCD}&=&(x+6)^2(x-6) \\ \\ \dfrac{x+1}{x^2-36}\cdot \dfrac{(x+6)}{(x+6)}&\Rightarrow &\dfrac{x^2+7x+6}{(x+6)^2(x-6)} \\ \\ \dfrac{(2x+3)}{(x^2+12x+36)}\cdot \dfrac{(x-6)}{(x-6)}&\Rightarrow &\dfrac{2x^2-9x-18}{(x+6)^2(x-6)} \end{array}[/latex]
  • [latex]\begin{array}[t]{rrl} \text{LCD}&=&(x-4)(x+3)(x+1) \\ \\ \dfrac{(3x+1)}{(x^2-x-12)}\cdot \dfrac{(x+1)}{(x+1)}&\Rightarrow & \dfrac{3x^2+4x+1}{(x-4)(x+3)(x+1)} \\ \\ \dfrac{2x}{(x^2+4x+3)}\cdot \dfrac{(x-4)}{(x-4)}&\Rightarrow & \dfrac{2x^2-8x}{(x-4)(x+3)(x+1)} \end{array}[/latex]
  • [latex]\begin{array}[t]{rrl} \text{LCD}&=&(x-3)(x+2) \\ \\ \dfrac{4x}{x^2-x-6}&\Rightarrow &\dfrac{4x}{(x-3)(x+2)} \\ \\ \dfrac{(x+2)}{(x-3)}\cdot \dfrac{(x+2)}{(x+2)}&\Rightarrow &\dfrac{x^2+4x+4}{(x-3)(x+2)} \end{array}[/latex]
  • [latex]\begin{array}[t]{rrl} \text{LCD}&=&(x-4)(x-2)(x+5) \\ \\ \dfrac{3x}{x^2-6x+8}\cdot \dfrac{(x+5)}{(x+5)}&\Rightarrow & \dfrac{3x^2+15x}{(x-4)(x-2)(x+5)} \\ \\ \dfrac{(x-2)}{(x^2+x-20)}\cdot \dfrac{(x-2)}{(x-2)}&\Rightarrow & \dfrac{x^2-4x+4}{(x-4)(x-2)(x+5)} \\ \\ \dfrac{5}{(x^2+3x-10)}\cdot \dfrac{(x-4)}{(x-4)}&\Rightarrow & \dfrac{5x-20}{(x-4)(x-2)(x+5)} \end{array}[/latex]

Intermediate Algebra Copyright © 2020 by Terrance Berg is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International License , except where otherwise noted.

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Big Ideas Math Answers for Grade K, 1, 2, 3, 4, 5, 6, 7, 8, Algebra 1, 2 & Geometry

Big Ideas Math Answers Common Core 2023 Curriculum Free PDF: To those students who are looking for common core 2019 BigIdeas Math Answers & Resources for all grades can check here. We have made it easy now to discover Pdf formatted Big Idea Math Book Answers without digging deep. Have access to our online Big Ideas Math Textbook Answers of Common Core 2023 Students edition from this page or save them on your devices without a single penny. By accessing these Big Ideas Math Solutions Key Pdf , you own convenient answers to all mathematical concepts from Grade K to High School subjects.

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Can’t Find Eclipse Glasses? Here’s What to Do.

You can watch a projection of the eclipse using some common household items.

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Two people kneel near an open cardboard box that they’ve fashioned into a projector for viewing an eclipse.

By Katrina Miller

Follow our live updates on the total solar eclipse .

Reliable paper-framed glasses are by far the most popular option for safely watching the total solar eclipse on Monday. But they’ve gotten more difficult to find in some places ahead of the event.

If you’ve checked everywhere — your local planetarium, public library and even online — fear not: There is still a way to watch the eclipse safely, using items around the house. Here are a few options.

Use your hands

Palms up, position one hand over the other at a 90-degree angle. Open your fingers slightly in a waffle pattern, and allow sunlight to stream through the spaces onto the ground, or another surface. During the eclipse, you will see a projection of the moon obscuring the surface of the sun.

This method works with anything with holes, such as a straw hat, a strainer, a cheese grater or even a perforated spoon. You will also notice this effect when light from the partially eclipsed sun streams through leaves on a tree.

Set up a cardstock screen

For this option, you need a couple of white index cards or two sheets of cardstock paper. First, punch a small hole in the middle of one of the cards using a thumbtack or a pin.

Then, facing away from the sun, allow light to stream through this pinhole. Position the second card underneath to function as a screen. Adjust the spacing between the two cards to make the projection of the sun larger or smaller.

Make a box projector

If you’re up for a bit of crafting, you can make a more sophisticated pinhole projector . Start with a cardboard box — empty cereal boxes are often used, but you can use a larger box, too. You’ll also need scissors, white paper, tape, aluminum foil and a pin or thumbtack.

Cut the piece of paper to fit the inside bottom of the cardboard box to act as a screen. Use tape to hold it in place.

On the top of the box, cut two rectangular holes on either side. (The middle should be left intact — you can use tape to secure this if needed.)

Tape a piece of aluminum foil over one of the rectangular cutouts. Punch a tiny hole in the middle of the foil with the tack or pin. The other cutout will serve as a view hole.

With your back to the sun, position the foil side of the box over your shoulder, letting light stream through the pinhole. An image of the sun will project onto the screen at the bottom of the box, which you can see through the view hole. A bigger box will create a bigger image.

Enjoy the show through any of these makeshift pinholes. And remember, during totality, you can view the sun directly with your naked eye. But you should stop looking at the sun as soon as it reappears.

Katrina Miller is a science reporting fellow for The Times. She recently earned her Ph.D. in particle physics from the University of Chicago. More about Katrina Miller

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  6. Lesson 20 Homework ( Unit 8 Vocab + Grammar If Conditionals ) -Mr. Hany Magdy -2024 for 3rd. Sec

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